Question

<module 4a
magnetic force on charged particles conceptual question
for each of the situations below, a charged particle enters a region of uniform magnetic field. determine the direction of the force on each charge due to the magnetic field
figure
part b
determine the direction of the force on the charge due to the magnetic field. (figure 2)
review | constants
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f points into the page.
f points out of the page.
f points neither into nor out of the page and f≠0.
f = 0.
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only the component of the magnetic field that is perpendicular to the velocity of the charged particle causes a force on the particle. if there is no perpendicular component, then there can be no force.

Explanation:

Step1: Recall the formula for magnetic force

The magnetic force on a charged - particle is given by $\vec{F}=q\vec{v}\times\vec{B}$, where $q$ is the charge of the particle, $\vec{v}$ is the velocity vector of the particle, and $\vec{B}$ is the magnetic - field vector. The direction of the cross - product $\vec{v}\times\vec{B}$ can be determined using the right - hand rule.

Step2: Identify the velocity and magnetic - field directions in the given figure

In the figure, assume the velocity $\vec{v}$ of the positively charged particle ($q>0$) is in the upward direction and the magnetic field $\vec{B}$ is in the right - hand direction.

Step3: Apply the right - hand rule

Point the fingers of your right hand in the direction of $\vec{v}$ (upward) and curl them towards the direction of $\vec{B}$ (right - hand direction). Your thumb will point out of the page. Since $q>0$, the direction of the force $\vec{F}=q\vec{v}\times\vec{B}$ is out of the page.

Answer:

$\vec{F}$ points out of the page.