Question

a mother shows a punnett - square where two parents that are heterozygous for dimples are crossed. dominant (d) are dominant to recessive (d). using the punnett square, what is the percent chance that the offspring will have dimples? a. 25% b. 50% c. 75% d. 100%

Explanation:

Step1: Count total genotypes

There are 4 genotypes in the Punnett - square: DD, Dd, Dd, dd.

Step2: Count non - dominant genotypes

The non - dominant genotype is dd. There is 1 dd genotype out of 4.

Step3: Calculate percentage

The percentage is $\frac{1}{4}\times100\% = 25\%$.

Answer:

C. 25%