Question

the mounting bracket shown was purchased at a hardware store. find the diameter of the hole, which is the distance across it. the diameter of the hole is \\(\square\\) inch(es) (simplify your answer. type a whole number, fraction, or mixed number.)

Explanation:

Step1: Convert to common denominator

$\frac{5}{16} = \frac{10}{32}$

Step2: Calculate total side gaps

$2 \times \frac{10}{32} = \frac{20}{32}$

Step3: Subtract gaps from total width

$\frac{31}{32} - \frac{20}{32} = \frac{11}{32}$

Wait, correction:

Step1: Convert fraction to common denominator

$\frac{5}{16} = \frac{10}{32}$

Step2: Sum the two side distances

$\frac{10}{32} + \frac{10}{32} = \frac{20}{32}$

Step3: Subtract from total width

$\frac{31}{32} - \frac{20}{32} = \frac{11}{32}$

Answer:

$\frac{1}{32}$ inch