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Question

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simplify: (\frac{\frac{2}{x}+\frac{1}{3x^2}}{1+\frac{1}{6x}})
(\bigcirc) (\frac{2}{x})
(\bigcirc) (\frac{12x + 2}{6x^2 + x})
(\bigcirc) (2x)
(\bigcirc) (\frac{4}{x})

Explanation:

Step1: Simplify the numerator of the complex fraction

The numerator is $\frac{2}{x} + \frac{1}{3x^2}$. Find a common denominator, which is $3x^2$.
$\frac{2}{x} = \frac{2\times3x}{x\times3x} = \frac{6x}{3x^2}$
So, $\frac{2}{x} + \frac{1}{3x^2} = \frac{6x}{3x^2} + \frac{1}{3x^2} = \frac{6x + 1}{3x^2}$

Step2: Simplify the denominator of the complex fraction

The denominator is $1 + \frac{1}{6x}$. Find a common denominator, which is $6x$.
$1 = \frac{6x}{6x}$
So, $1 + \frac{1}{6x} = \frac{6x}{6x} + \frac{1}{6x} = \frac{6x + 1}{6x}$

Step3: Divide the simplified numerator by the simplified denominator

We have the complex fraction $\frac{\frac{6x + 1}{3x^2}}{\frac{6x + 1}{6x}}$. Dividing by a fraction is multiplying by its reciprocal:
$\frac{6x + 1}{3x^2} \times \frac{6x}{6x + 1}$

Step4: Cancel out common factors

The $(6x + 1)$ terms cancel out, and we can simplify the $x$ and constant terms:
$\frac{6x}{3x^2} = \frac{6}{3x} = \frac{2}{x}$ (Wait, no, wait. Wait, 6x divided by 3x²: 6/3 is 2, x/x² is 1/x, so 2/x? Wait, no, let's check again. Wait, 6x in numerator, 3x² in denominator. So 6/3 is 2, x/x² is 1/x, so 2/x? But wait, let's do the multiplication again. Wait, $\frac{6x + 1}{3x^2} \times \frac{6x}{6x + 1}$: the (6x + 1) cancels, so we have (6x)/(3x²) = (6)/(3x) = 2/x? Wait, but that's one of the options, but let's check the options again. Wait, no, maybe I made a mistake. Wait, wait, the numerator after step1: $\frac{2}{x} + \frac{1}{3x^2}$: common denominator 3x², so 23x/(3x²) + 1/(3x²) = (6x + 1)/(3x²). Denominator: 1 + 1/(6x) = (6x + 1)/(6x). Then the complex fraction is [(6x + 1)/(3x²)] / [(6x + 1)/(6x)] = [(6x + 1)/(3x²)] [6x/(6x + 1)] = (6x)/(3x²) = 2/x. Wait, but option B is (12x + 2)/(6x² + x). Wait, maybe my initial simplification of the numerator was wrong. Wait, let's re-express the original numerator: $\frac{2}{x} + \frac{1}{3x^2}$. Let's get a common denominator of 3x²: 2/x = 6x/(3x²), so 6x/(3x²) + 1/(3x²) = (6x + 1)/(3x²). Denominator: 1 + 1/(6x) = (6x + 1)/(6x). Then the fraction is [(6x + 1)/(3x²)] / [(6x + 1)/(6x)] = (6x + 1)/(3x²) * 6x/(6x + 1) = 6x/(3x²) = 2/x. But option B is (12x + 2)/(6x² + x). Let's check if that's equivalent to 2/x. Let's factor numerator and denominator of B: numerator 12x + 2 = 2(6x + 1), denominator 6x² + x = x(6x + 1). So (2(6x + 1))/(x(6x + 1)) = 2/x. Oh! So option B simplifies to 2/x? Wait, no, wait: (12x + 2)/(6x² + x) = 2(6x + 1)/(x(6x + 1)) = 2/x. So both the result we got and option B are equivalent? Wait, but let's check the options again. Wait, the options are:

A. 2/x

B. (12x + 2)/(6x² + x)

C. 2x

D. 4/x

Wait, so when we simplified, we got 2/x, which is option A. But option B, when simplified, also gives 2/x. Wait, maybe I made a mistake in the initial steps. Wait, let's re-express the original problem:

The original expression is $\frac{\frac{2}{x} + \frac{1}{3x^2}}{1 + \frac{1}{6x}}$

Let's multiply numerator and denominator by 6x² to eliminate all denominators.

Numerator: 6x²($\frac{2}{x} + \frac{1}{3x^2}$) = 6x²(2/x) + 6x²*(1/3x²) = 12x + 2

Denominator: 6x²(1 + $\frac{1}{6x}$) = 6x²1 + 6x²*(1/6x) = 6x² + x

So the expression becomes (12x + 2)/(6x² + x), which is option B. And when we simplify option B, we get 2/x, but the question is to simplify the original expression, and option B is a simplified form (maybe not the most simplified, but let's check the options). Wait, but when we did the first method, we got 2/x, which is option A. But there's a contradiction here. Wait, no, let's check the multiplication by 6x². Let's do that:

Multiply numerator and…

Answer:

A. $\frac{2}{x}$