Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. santos takes the train into the city five days a week for work. for one work week, he kept track of how many minutes long each train ride was: 48 51 48 48 50 calculate the mean, median, range, and midrange of the train ride times for the week. ○ mean, 3; median, 49.5; range, 49; midrange, 48 ○ mean, 49.5; median, 49; range, 48; midrange, 3 ○ mean, 49; median, 48; range, 3; midrange, 49.5 ○ mean, 48; median, 3; range, 49.5; midrange, 49

Explanation:

Step1: Order the data

First, we order the data set \( 48, 51, 48, 48, 50 \) from least to greatest: \( 48, 48, 48, 50, 51 \)

Step2: Calculate the Mean

The mean is the sum of the data divided by the number of data points. The sum of the data is \( 48 + 48 + 48 + 50 + 51 = 245 \). There are 5 data points, so the mean is \( \frac{245}{5} = 49 \)

Step3: Calculate the Median

The median is the middle value when the data is ordered. For a set with 5 data points (odd number), the median is the 3rd value. In the ordered set \( 48, 48, 48, 50, 51 \), the 3rd value is \( 48 \)

Step4: Calculate the Range

The range is the difference between the maximum and minimum values. The maximum value is \( 51 \) and the minimum is \( 48 \), so the range is \( 51 - 48 = 3 \)

Step5: Calculate the Midrange

The midrange is the average of the maximum and minimum values. So, \( \frac{48 + 51}{2} = \frac{99}{2} = 49.5 \)

Answer:

Mean, 49; Median, 48; Range, 3; Midrange, 49.5 (which corresponds to the second option: "Mean, 49; Median, 48; Range, 3; Midrange, 49.5")