QUESTION IMAGE
Question
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depend evaluate $2x^3 - 3x^2 + 4$ for $x = -2$. \bigcirc 0 \bigcirc -24 \bigcirc 8 \bigcirc 32
Step1: Substitute \( x = -2 \) into the first term \( 2x^3 \)
First, calculate \( x^3 \) when \( x = -2 \). \( (-2)^3 = -8 \). Then multiply by 2: \( 2\times(-8) = -16 \)
Step2: Substitute \( x = -2 \) into the second term \( -3x^2 \)
Calculate \( x^2 \) when \( x = -2 \). \( (-2)^2 = 4 \). Then multiply by -3: \( -3\times4 = -12 \)
Step3: Add the constant term and the results from Step1 and Step2
Now we have the three parts: \( -16 \) (from Step1), \( -12 \) (from Step2), and \( +4 \) (the constant). Add them together: \( -16 + (-12) + 4 = -16 - 12 + 4 = -24 \)
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\(-24\) (corresponding to the option: \(-24\))