QUESTION IMAGE
Question
ms.math-07.snap2.desoto.v26 (copy) review
- which table does not represent a proportional relationship between x and y ?
a.
| x | 2 | 4 | 5 | 7 |
| y | 4 | 8 | 10 | 14 |
b.
| x | 1 | 4 | 5 | 6 |
| y | 3 | 12 | 15 | 14 |
c.
| x | 5 | 10 | 15 | 20 |
| y | 12 | 24 | 36 | 48 |
d.
| x | 1 | 3 | 5 | 6 |
| y | 1.5 | 4.5 | 7.5 | 9 |
- which two statements describe the location of the number represented by $-4\frac{1}{3} + 3\frac{3}{4}$ on a horizontal number line?
a. $3\frac{3}{4}$ units to the left of $4\frac{1}{3}$
b. $3\frac{3}{4}$ units to the right of $-4\frac{1}{3}$
c. $4\frac{1}{3}$ units to the left of $3\frac{3}{4}$
d. $4\frac{1}{3}$ units to the right of $3\frac{3}{4}$
e. $4\frac{1}{3}$ units to the right of $-3\frac{3}{4}$
For Question 35:
Step1: Check ratio $\frac{y}{x}$ for Table A
$\frac{4}{2}=2$, $\frac{8}{4}=2$, $\frac{10}{5}=2$, $\frac{14}{7}=2$
Step2: Check ratio $\frac{y}{x}$ for Table B
$\frac{3}{1}=3$, $\frac{12}{4}=3$, $\frac{15}{5}=3$, $\frac{14}{6}\approx2.33$
Step3: Check ratio $\frac{y}{x}$ for Table C
$\frac{12}{5}=2.4$, $\frac{24}{10}=2.4$, $\frac{36}{15}=2.4$, $\frac{48}{20}=2.4$
Step4: Check ratio $\frac{y}{x}$ for Table D
$\frac{1.5}{1}=1.5$, $\frac{4.5}{3}=1.5$, $\frac{7.5}{5}=1.5$, $\frac{9}{6}=1.5$
Step1: Calculate the target value
Convert mixed numbers: $-4\frac{1}{3}=-\frac{13}{3}$, $3\frac{3}{4}=\frac{15}{4}$
Find common denominator: $-\frac{13}{3}+\frac{15}{4}=-\frac{52}{12}+\frac{45}{12}=-\frac{7}{12}$
Step2: Verify Option A
Location: $4\frac{1}{3}-3\frac{3}{4}=\frac{13}{3}-\frac{15}{4}=\frac{52-45}{12}=\frac{7}{12}
eq-\frac{7}{12}$
Step3: Verify Option B
Location: $-4\frac{1}{3}+3\frac{3}{4}=-\frac{13}{3}+\frac{15}{4}=-\frac{7}{12}$, matches the value
Step4: Verify Option C
Location: $3\frac{3}{4}-4\frac{1}{3}=\frac{15}{4}-\frac{13}{3}=\frac{45-52}{12}=-\frac{7}{12}$, matches the value
Step5: Verify Option D
Location: $3\frac{3}{4}+4\frac{1}{3}=\frac{15}{4}+\frac{13}{3}=\frac{45+52}{12}=\frac{97}{12}
eq-\frac{7}{12}$
Step6: Verify Option E
Location: $-3\frac{3}{4}+4\frac{1}{3}=-\frac{15}{4}+\frac{13}{3}=\frac{-45+52}{12}=\frac{7}{12}
eq-\frac{7}{12}$
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B.
| $x$ | 1 | 4 | 5 | 6 |
|---|
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