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ms.math-07.snap2.desoto.v26 (copy) review 35. which table does not repr…

Question

ms.math-07.snap2.desoto.v26 (copy) review

  1. which table does not represent a proportional relationship between x and y ?

a.

x2457
y481014

b.

x1456
y3121514

c.

x5101520
y12243648

d.

x1356
y1.54.57.59
  1. which two statements describe the location of the number represented by $-4\frac{1}{3} + 3\frac{3}{4}$ on a horizontal number line?

a. $3\frac{3}{4}$ units to the left of $4\frac{1}{3}$
b. $3\frac{3}{4}$ units to the right of $-4\frac{1}{3}$
c. $4\frac{1}{3}$ units to the left of $3\frac{3}{4}$
d. $4\frac{1}{3}$ units to the right of $3\frac{3}{4}$
e. $4\frac{1}{3}$ units to the right of $-3\frac{3}{4}$

Explanation:

Response
For Question 35:

Step1: Check ratio $\frac{y}{x}$ for Table A

$\frac{4}{2}=2$, $\frac{8}{4}=2$, $\frac{10}{5}=2$, $\frac{14}{7}=2$

Step2: Check ratio $\frac{y}{x}$ for Table B

$\frac{3}{1}=3$, $\frac{12}{4}=3$, $\frac{15}{5}=3$, $\frac{14}{6}\approx2.33$

Step3: Check ratio $\frac{y}{x}$ for Table C

$\frac{12}{5}=2.4$, $\frac{24}{10}=2.4$, $\frac{36}{15}=2.4$, $\frac{48}{20}=2.4$

Step4: Check ratio $\frac{y}{x}$ for Table D

$\frac{1.5}{1}=1.5$, $\frac{4.5}{3}=1.5$, $\frac{7.5}{5}=1.5$, $\frac{9}{6}=1.5$

Step1: Calculate the target value

Convert mixed numbers: $-4\frac{1}{3}=-\frac{13}{3}$, $3\frac{3}{4}=\frac{15}{4}$
Find common denominator: $-\frac{13}{3}+\frac{15}{4}=-\frac{52}{12}+\frac{45}{12}=-\frac{7}{12}$

Step2: Verify Option A

Location: $4\frac{1}{3}-3\frac{3}{4}=\frac{13}{3}-\frac{15}{4}=\frac{52-45}{12}=\frac{7}{12}
eq-\frac{7}{12}$

Step3: Verify Option B

Location: $-4\frac{1}{3}+3\frac{3}{4}=-\frac{13}{3}+\frac{15}{4}=-\frac{7}{12}$, matches the value

Step4: Verify Option C

Location: $3\frac{3}{4}-4\frac{1}{3}=\frac{15}{4}-\frac{13}{3}=\frac{45-52}{12}=-\frac{7}{12}$, matches the value

Step5: Verify Option D

Location: $3\frac{3}{4}+4\frac{1}{3}=\frac{15}{4}+\frac{13}{3}=\frac{45+52}{12}=\frac{97}{12}
eq-\frac{7}{12}$

Step6: Verify Option E

Location: $-3\frac{3}{4}+4\frac{1}{3}=-\frac{15}{4}+\frac{13}{3}=\frac{-45+52}{12}=\frac{7}{12}
eq-\frac{7}{12}$

Answer:

B.

$x$1456

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For Question 40: