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Question
multiple choice question 2 solve for x. \\(\frac{3}{4} = \frac{x}{x + 1}\\) a \\(x = 3\\) b \\(x = 1\\) c \\(x = -1\\) d \\(x = \frac{3}{4}\\)
Step1: Cross - multiply the equation
Given the equation \(\frac{3}{4}=\frac{x}{x + 1}\), cross - multiplying (which is based on the property that if \(\frac{a}{b}=\frac{c}{d}\), then \(a\times d=b\times c\)) gives us \(3(x + 1)=4x\).
Step2: Expand the left - hand side
Expanding \(3(x + 1)\) using the distributive property \(a(b + c)=ab+ac\) (here \(a = 3\), \(b=x\), \(c = 1\)), we get \(3x+3 = 4x\).
Step3: Solve for \(x\)
Subtract \(3x\) from both sides of the equation \(3x+3 = 4x\). So, \(3x+3-3x=4x - 3x\), which simplifies to \(3=x\) or \(x = 3\).
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A. \(x = 3\)