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multiplication prope 5 \\(\\frac{b}{2} < -3\\)

Question

multiplication prope 5 \\(\frac{b}{2} < -3\\)

Explanation:

Step1: Identify the inequality

We have the inequality $\frac{b}{2} < -3$. To solve for $b$, we need to isolate $b$ on one side of the inequality.

Step2: Multiply both sides by 2

Since we want to get rid of the denominator 2, we multiply both sides of the inequality by 2. When we multiply both sides of an inequality by a positive number, the direction of the inequality sign remains the same. So we have:

$$ \frac{b}{2} \times 2 < -3 \times 2 $$

Step3: Simplify both sides

Simplifying the left side, $\frac{b}{2} \times 2 = b$. Simplifying the right side, $-3 \times 2 = -6$. So we get:

$$ b < -6 $$

Answer:

$b < -6$