Question

name:date:solutions. then, select a choice.incorrect answers will stay red.7. one solution, no solution, or infinite solutions?$8(-x \cdot 2) = -3x \cdot 16 - 5x$10. one solution, no solution, or infinite solutions?$4(x \cdot 2) = 2x \cdot 16$

Explanation:

Step1: Expand left-hand side

$8(-x \cdot 2) = 8(-2x) = -16x$

Step2: Simplify right-hand side

$-3x + 16 - 5x = -8x + 16$

Step3: Rearrange to isolate x terms

$-16x + 8x = 16$

Step4: Combine like terms

$-8x = 16$

Step5: Solve for x

$x = \frac{16}{-8} = -2$

(for problem 10):

Step1: Expand left-hand side

$4(x \cdot 2) = 4(2x) = 8x$

Step2: Simplify right-hand side

$2x \cdot 16 = 32x$

Step3: Rearrange to isolate x terms

$8x - 32x = 0$

Step4: Combine like terms

$-24x = 0$

Step5: Solve for x

$x = \frac{0}{-24} = 0$

Answer:

One Solution, $x=-2$

---