Question

for nitrogen to be a liquid, its temperature must be within 12.78 °f of -333.22 °f. which equation can be used to find the maximum and minimum temperatures at which nitrogen is a liquid, x? the equation that can be used to find the maximum and minimum temperatures is |x + | = .

Explanation:

Step1: Understand absolute - value equation concept

The general form of an absolute - value equation for the distance between a variable \(x\) and a constant \(a\) is \(|x - a|=b\), where \(b\) is the distance. Here, the target temperature is \(a=- 333.22^{\circ}F\) and the allowable distance from this temperature is \(b = 12.78^{\circ}F\). We can rewrite \(|x-(-333.22)|=12.78\).

Step2: Simplify the equation

Since \(x-(-333.22)=x + 333.22\), the equation becomes \(|x + 333.22|=12.78\).

Answer:

\(|x + 333.22|=12.78\)