Question

do now how much energy is absorbed to turn 100 g of water at 20℃ into steam? $c_p = 4.184 j/(gcdot℃)$ $h_{vaporization}=2260 j/g$

Explanation:

Step1: Calculate heat to raise temperature to 100°C

Use the formula $Q_1 = mc\Delta T$, where $m = 100g$, $c = 4.184J/(g\cdot^{\circ}C)$ and $\Delta T=100 - 20=80^{\circ}C$.
$Q_1=100\times4.184\times80 = 33472J$

Step2: Calculate heat for vaporization

Use the formula $Q_2 = mH_{vaporization}$, where $m = 100g$ and $H_{vaporization}=2260J/g$.
$Q_2=100\times2260 = 226000J$

Step3: Calculate total heat

$Q = Q_1+Q_2$.
$Q=33472 + 226000=259472J$

Answer:

$259472J$