Question

on a number line, plot all possible values of x. -1.5 ≤ x ≤ 4 answer: tools: ray segment eraser your action: please select tool. number line from -10 to 10 with -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Explanation:

Step1: Identify the interval

The inequality is \(-1.5 \leq x \leq 4\), which means \(x\) is between \(-1.5\) and \(4\) (including both endpoints).

Step2: Locate endpoints on number line

• Find \(-1.5\) on the number line (halfway between \(-2\) and \(-1\)).
• Find \(4\) on the number line.

Step3: Draw the segment

Since \(x\) includes all values from \(-1.5\) to \(4\), we use the "Segment" tool to draw a line segment connecting the points at \(-1.5\) and \(4\) on the number line. We also mark the endpoints (closed circles) because the inequality includes the endpoints (\(\leq\) and \(\geq\) - here both are included as \(-1.5 \leq x \leq 4\)).

Answer:

To plot \( -1.5 \leq x \leq 4 \) on the number line:

1. Use the "Segment" tool.
2. Place a closed circle at \( x = -1.5 \) (halfway between \(-2\) and \(-1\)) and at \( x = 4 \).
3. Draw a line segment connecting these two closed circles to represent all values of \( x \) between (and including) \(-1.5\) and \(4\).