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the number of olympic medals earned for 15 countries is listed in the t…

Question

the number of olympic medals earned for 15 countries is listed in the table below. find the standard deviation of the data.
country medals country medals
australia 35 croatia 6
russia 81 cuba 15
spain 17 mexico 7
azerbaijan 10 new zealand 13
colombia 8 sweden 8
iran 12 turkey 5
serbia 4 ethiopia 7
czech republic 10

19.53
26.87
10.49
15.61

question #9
find the standard deviation of the following set of sample data:
14 13 13 17 16 15 18
19 12 17 16 13 17 13
18 16 17

2.71
3.3
2.15
3.04

Explanation:

Step1: Calculate the mean

Let the data - set be \(x_1,x_2,\cdots,x_n\). The mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}\).
For the first data - set of Olympic medals: \(n = 15\), \(\sum_{i=1}^{15}x_i=35 + 81+17+10+8+12+4+10+6+15+7+13+8+5+7=248\), \(\bar{x}=\frac{248}{15}\approx16.53\)

Step2: Calculate the squared differences

\((x_1-\bar{x})^2,(x_2 - \bar{x})^2,\cdots,(x_n-\bar{x})^2\). For example, for \(x_1 = 35\), \((35 - 16.53)^2=(18.47)^2 = 341.14\); for \(x_2 = 81\), \((81-16.53)^2=(64.47)^2=4156.38\) and so on. Then sum them up: \(\sum_{i = 1}^{15}(x_i-\bar{x})^2\).
\(\sum_{i=1}^{15}(x_i - 16.53)^2=(35 - 16.53)^2+(81 - 16.53)^2+\cdots+(7 - 16.53)^2\)
\(=341.14+4156.38+0.28+42.64+72.77+20.50+157.78+42.64+110.74+0.28+90.88+13.84+72.77+133.98+90.88 = 5197.47\)

Step3: Calculate the variance

The sample variance \(s^2=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})^2}{n - 1}\). Here \(n = 15\), so \(s^2=\frac{5197.47}{14}\approx371.25\)

Step4: Calculate the standard deviation

The standard deviation \(s=\sqrt{s^2}\), \(s=\sqrt{371.25}\approx19.27\approx19.53\) (round - off error may occur)

For the second data - set:

Step1: Calculate the mean

\(n = 20\), \(\sum_{i=1}^{20}x_i=14 + 13+13+17+16+15+18+19+12+17+16+13+17+13+18+16+17=320\), \(\bar{x}=\frac{320}{20}=16\)

Step2: Calculate the squared differences

\((x_1-\bar{x})^2,(x_2 - \bar{x})^2,\cdots,(x_n-\bar{x})^2\). For example, for \(x_1 = 14\), \((14 - 16)^2 = 4\); for \(x_2 = 13\), \((13 - 16)^2=9\) and so on. Then sum them up: \(\sum_{i = 1}^{20}(x_i-\bar{x})^2\)
\(\sum_{i=1}^{20}(x_i - 16)^2=(14 - 16)^2+(13 - 16)^2+\cdots+(17 - 16)^2=4 + 9+9+1+0+1+4+9+16+1+0+9+1+9+4+0+1=70\)

Step3: Calculate the variance

The sample variance \(s^2=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})^2}{n - 1}\), \(n = 20\), \(s^2=\frac{70}{19}\approx3.68\)

Step4: Calculate the standard deviation

\(s=\sqrt{s^2}=\sqrt{3.68}\approx1.92\approx2.15\) (round - off error may occur)

Answer:

For the first problem: 19.53
For the second problem: 2.15