Question

2 numeric 1 point
given:
$f(x)=\

$$\begin{cases} -2x & \\text{if } x < -1 \\\\ 3x-1 & \\text{if } -1\\leq x \\leq 2 \\\\ -\\dfrac{1}{2}x & \\text{if } x > 2 \\end{cases}$$

$
find $f(-1)+3f(8)-2f(-3)$
answer
-22

Explanation:

Step1: Calculate $f(-1)$

Use $3x-1$ (since $-1 \leq -1 \leq 2$):
$f(-1)=3(-1)-1=-3-1=-4$

Step2: Calculate $f(8)$

Use $-\frac{1}{2}x$ (since $8>2$):
$f(8)=-\frac{1}{2}(8)=-4$

Step3: Calculate $f(-3)$

Use $-2x$ (since $-3<-1$):
$f(-3)=-2(-3)=6$

Step4: Compute the final expression

Substitute values into $f(-1)+3f(8)-2f(-3)$:
$(-4)+3(-4)-2(6)=-4-12-12=-22$

Answer:

-22