Question

an object is launched from a platform. its height (in meters), ( x ) seconds after the launch, is modeled by ( h(x) = -5(x + 1)(x - 9) ) what is the height of the object at the time of launch? (square) meters show calculator

Explanation:

Step1: Determine the time of launch

The time of launch is when \( x = 0 \) (since \( x \) is the number of seconds after launch).

Step2: Substitute \( x = 0 \) into the height function

We have the height function \( h(x)=-5(x + 1)(x - 9) \). Substitute \( x = 0 \) into the function:
\( h(0)=-5(0 + 1)(0 - 9) \)

Step3: Simplify the expression

First, simplify the terms inside the parentheses: \( 0 + 1=1 \) and \( 0 - 9=-9 \). Then we have:
\( h(0)=-5\times1\times(-9) \)
Multiply the numbers: \( -5\times1=-5 \), and then \( -5\times(-9) = 45 \)

Answer:

\( 45 \)