Question

1. one spinner has 6 equal parts labeled with the letters a through f.another spinner has 3 equal part labeled with the numbers 1, 2, and 3.what is the probability of spinning a c and a 2?$\frac{1}{8}$$\frac{1}{18}$$\frac{1}{9}$$\frac{1}{3}$

Explanation:

Step1: Probability of spinning C

The first spinner has 6 equal parts, so the probability of landing on C is $\frac{1}{6}$.

Step2: Probability of spinning 2

The second spinner has 3 equal parts, so the probability of landing on 2 is $\frac{1}{3}$.

Step3: Multiply the two probabilities

For independent events, multiply their individual probabilities: $\frac{1}{6} \times \frac{1}{3}$

Answer:

$\frac{1}{18}$ (corresponding to the second option: $\boldsymbol{\frac{1}{18}}$)