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a parabola has a vertex at (-3,2). where is the axis of symmetry? y = -…

Question

a parabola has a vertex at (-3,2). where is the axis of symmetry?
y = -2
y = 2
x = 3
x = -3
7/50

Explanation:

Step1: Recall axis - of - symmetry property

The axis of symmetry of a parabola passes through its vertex. For a parabola with a vertex at $(h,k)$ in the form $(x - h)^2=4p(y - k)$ (vertical parabola) or $(y - k)^2 = 4p(x - h)$ (horizontal parabola), the equation of the axis of symmetry for a vertical parabola is $x=h$ and for a horizontal parabola is $y = k$.

Step2: Identify the vertex coordinates

The vertex of the parabola is given as $(-3,2)$. Here $h=-3$ and $k = 2$. Since the standard - form of a vertical parabola has an axis of symmetry $x=h$, substituting $h=-3$ into the equation of the axis of symmetry.

Answer:

$x=-3$