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a parked car starts to move and reaches a velocity of 75 m/s in 10 seco…

Question

a parked car starts to move and reaches a velocity of 75 m/s in 10 seconds. the initial velocity of the car is 0 m/s and its final velocity is 75 m/s. acceleration = final velocity - initial velocity / time interval which of the following are examples of acceleration? a car speeds up after getting on a highway. a car travels at a constant velocity on a highway. a car slows down to exit a highway. a car rounds a sharp curve on a highway.

Explanation:

Step1: Identify values

Initial velocity $u = 0$ m/s, final velocity $v=75$ m/s, time $t = 10$ s.

Step2: Apply acceleration formula

$a=\frac{v - u}{t}=\frac{75 - 0}{10}$

Step3: Calculate acceleration

$a=\frac{75}{10}=7.5$ m/s²

For the multiple - choice question:
Acceleration is a change in velocity. A car speeds up after getting on a highway has a change in velocity, so it has acceleration. A car traveling at a constant velocity has no acceleration as there is no change in velocity. A car slowing down to exit a highway has negative acceleration (deceleration). A car rounding a sharp curve changes its direction of velocity (even if speed is constant, velocity is a vector), so it has acceleration.

Answer:

For the calculation part: $7.5$ m/s²
For the multiple - choice part: A car speeds up after getting on a highway; A car slows down to exit a highway; A car rounds a sharp curve on the highway.