Question

part iv: density
you have learned that density can be calculated from this equation: ( d = \frac{m}{v} ), where ( d ) is an object’s density, ( m ) is an object’s mass, and ( v ) is an object’s volume. let us about density to solve these problems;
a piece of aluminum has a volume of ( 12 , \text{cm}^3 ) and a mass of ( 32 , \text{g} ). what is its density? do not forget the units.
solution:

Explanation:

Step1: Identify formula and values

We use the density formula \( D=\frac{m}{v} \), where \( m = 32\space g \) and \( v=12\space cm^3 \).

Step2: Substitute values into formula

Substitute \( m = 32\) and \( v = 12 \) into \( D=\frac{m}{v} \), we get \( D=\frac{32}{12}\space g/cm^3 \).

Step3: Simplify the fraction

Simplify \( \frac{32}{12}=\frac{8}{3}\approx2.67\space g/cm^3 \).

Answer:

The density of the aluminum is \(\frac{8}{3}\space g/cm^3\) (or approximately \(2.67\space g/cm^3\))