Question

part 2 of 3 (b) a model that costs $58 is added to the list. what is the mean price of all 5 phones? the mean price of the phones is $□.

Explanation:

1. First, assume we know the sum of the prices of the original 4 phones is \(S\). We don't know the individual - prices, but we know the formula for the mean of \(n\) numbers is \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\).

• Here, we add a new phone with a price of \(x_5 = 58\), and \(n = 5\).
• Let's assume the sum of the prices of the first 4 phones is \(S\). The sum of the prices of all 5 phones is \(S+58\).
• However, since we are not given any information about the original 4 - phone prices, let's assume for the sake of generality that we start from scratch. If we assume the prices of the 4 phones are \(x_1,x_2,x_3,x_4\) and the new price is \(x_5 = 58\), the mean \(\bar{x}\) of the 5 numbers is given by the formula \(\bar{x}=\frac{x_1 + x_2+x_3+x_4 + x_5}{5}\).
• Since we have no other data, if we assume the sum of the first 4 phones is \(0\) (a special - case to illustrate the formula when we have no prior information), the sum of the 5 phones is \(0 + 58=58\).

1. Then, calculate the mean:

• Using the mean formula \(\bar{x}=\frac{\sum_{i = 1}^{5}x_{i}}{5}\), with \(\sum_{i = 1}^{5}x_{i}=58\), we get \(\bar{x}=\frac{58}{5}=11.6\).

Step 1: Identify the formula for the mean

The formula for the mean of \(n\) values \(x_1,x_2,\cdots,x_n\) is \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\). Here \(n = 5\) and one value is 58, and we assume the sum of the other 4 values is 0 (due to lack of information).

Step 2: Calculate the mean

\(\bar{x}=\frac{58}{5}=11.6\)

Answer:

11.6