Question

1. perform the following conversions: (a) 72.3 mg to g, (b) 6.0×10⁻¹⁰ m to mm, and (c) 325 mm to μm.

Explanation:

Step1: Recall mass - conversion factor

We know that $1\ g = 1000\ mg=10^{3}\ mg$. To convert $72.3\ mg$ to $g$, we use the conversion formula $m_{g}=\frac{m_{mg}}{10^{3}}$.
$m_{g}=\frac{72.3\ mg}{10^{3}\ mg/g}=7.23\times 10^{-2}\ g$

Step2: Recall length - conversion factor

We know that $1\ m = 1000\ mm = 10^{3}\ mm$. To convert $6.0\times 10^{-10}\ m$ to $mm$, we use the conversion formula $l_{mm}=l_{m}\times10^{3}$.
$l_{mm}=(6.0\times 10^{-10}\ m)\times10^{3}\ mm/m = 6.0\times 10^{-7}\ mm$

Step3: Recall length - conversion factor

We know that $1\ mm=1000\ \mu m = 10^{3}\ \mu m$. To convert $325\ mm$ to $\mu m$, we use the conversion formula $l_{\mu m}=l_{mm}\times10^{3}$.
$l_{\mu m}=(325\ mm)\times10^{3}\ \mu m/mm = 3.25\times 10^{5}\ \mu m$

Answer:

(a) $7.23\times 10^{-2}\ g$
(b) $6.0\times 10^{-7}\ mm$
(c) $3.25\times 10^{5}\ \mu m$