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a phlebotomist draws the blood of a random sample of 50 patients and de…

Question

a phlebotomist draws the blood of a random sample of 50 patients and determines their blood types as shown. complete parts (a) and (b). o a a a o b o b a o ab b a b ab o o a a o ab o a b a o a a o a o a o b a o ab a o o o a a o o o a o a o

Explanation:

Response

To solve this, we first count the frequency of each blood type:

Step 1: Count Blood Type Frequencies
  • Type A: Let's count. Looking at the list:
  • Row 1: A, A, A (3)
  • Row 2: O, B, A (1)
  • Row 3: B, A, AB (1)
  • Row 4: O, A, A (2)
  • Row 5: AB, O, A (1)
  • Row 6: O, A, A (2)
  • Row 7: O, A, O (1)
  • Row 8: O, AB, A (1)
  • Row 9: O, A, O (1)
  • Row 10: O, A, O (1)
  • Wait, better to count each:

Let's list all:
O, A, A, A, O,
B, O, B, A, O,
AB, B, A, B, AB,
O, O, A, A, O,
AB, O, A, B, A,
O, A, A, O, A,
O, A, O, B, A,
O, AB, A, A, O,
O, A, O, O, O,
O, A, O, A, O.

Now count A: Let's mark A's:
Row 1: A (3 times: positions 2,3,4)
Row 2: A (position 4)
Row 3: A (position 3)
Row 4: A (positions 3,4)
Row 5: A (positions 3,5)
Row 6: A (positions 2,3)
Row 7: A (position 2)
Row 8: A (positions 3,4)
Row 9: A (position 2)
Row 10: A (position 2,4)

Let's count: 3 +1 +1 +2 +2 +2 +1 +2 +1 +2 = Let's add: 3+1=4; 4+1=5; 5+2=7; 7+2=9; 9+2=11; 11+1=12; 12+2=14; 14+1=15; 15+2=17? Wait, maybe better to count all A's:

Let's list each A:

  1. A (row1, col2)
  2. A (row1, col3)
  3. A (row1, col4)
  4. A (row2, col4)
  5. A (row3, col3)
  6. A (row4, col3)
  7. A (row4, col4)
  8. A (row5, col3)
  9. A (row5, col5)
  10. A (row6, col2)
  11. A (row6, col3)
  12. A (row7, col2)
  13. A (row8, col3)
  14. A (row8, col4)
  15. A (row9, col2)
  16. A (row10, col2)
  17. A (row10, col4)

Wait, maybe I made a mistake. Let's count total patients: 10 rows ×5 columns =50. Let's count O, B, AB:

Type O: Let's count O's:

Row1: O (col1, col5) → 2
Row2: O (col2, col5) → 2
Row3: none
Row4: O (col1, col2, col5) →3
Row5: O (col2) →1
Row6: O (col1, col4) →2
Row7: O (col1, col3) →2
Row8: O (col1, col5) →2
Row9: O (col1, col3, col4, col5) →4
Row10: O (col1, col3, col5) →3

Total O: 2+2+3+1+2+2+2+4+3 = 21? Wait 2+2=4; +3=7; +1=8; +2=10; +2=12; +2=14; +4=18; +3=21.

Type B: Let's count B's:

Row1: none
Row2: B (col1, col3) →2
Row3: B (col2, col4) →2
Row4: none
Row5: B (col4) →1
Row6: none
Row7: B (col4) →1
Row8: none
Row9: none
Row10: none

Total B: 2+2+1+1=6.

Type AB: Let's count AB's:

Row1: none
Row2: none
Row3: AB (col1, col5) →2
Row4: none
Row5: AB (col1) →1
Row6: none
Row7: none
Row8: AB (col2) →1
Row9: none
Row10: none

Total AB: 2+1+1=4.

Now check total: A + O + B + AB = A +21 +6 +4 = A +31 =50 → A=19? Wait, maybe my counting is wrong. Let's use a better approach. Let's list all 50 entries:

Row 1: O, A, A, A, O → 5
Row 2: B, O, B, A, O →5
Row 3: AB, B, A, B, AB →5
Row 4: O, O, A, A, O →5
Row 5: AB, O, A, B, A →5
Row 6: O, A, A, O, A →5
Row 7: O, A, O, B, A →5
Row 8: O, AB, A, A, O →5
Row 9: O, A, O, O, O →5
Row10: O, A, O, A, O →5

Now count A in each row:

Row1: 3 (A's)
Row2: 1 (A)
Row3: 1 (A)
Row4: 2 (A's)
Row5: 2 (A's)
Row6: 3 (A's: positions 2,3,5)
Row7: 2 (A's: positions 2,5)
Row8: 2 (A's: positions 3,4)
Row9: 1 (A: position 2)
Row10: 2 (A's: positions 2,4)

Now sum: 3+1=4; +1=5; +2=7; +2=9; +3=12; +2=14; +2=16; +1=17; +2=19. Yes, A=19.

So frequencies:

  • A: 19
  • O: Let's count O in each row:

Row1: 2 (O's)
Row2: 2 (O's)
Row3: 0
Row4: 3 (O's)
Row5: 1 (O)
Row6: 2 (O's)
Row7: 2 (O's)
Row8: 2 (O's)
Row9: 4 (O's)
Row10: 3 (O's)
Sum: 2+2+3+1+2+2+2+4+3 = 21 (as before)

  • B: Row1:0; Row2:2; Row3:2; Row4:0; Row5:1; Row6:0; Row7:1; Row8:0; Row9:0; Row10:0 → 2+2+1+1=6
  • AB: Row1:0; Row2:0; Row3:2; Row4:0; Row5:1; Row6:…

Answer:

A