Question

a photon has a frequency of 4.5e8 hz. what is the energy of this photon? answer: j

Explanation:

Step1: Recall the energy - frequency formula

The energy of a photon is given by the formula $E = h
u$, where $E$ is the energy of the photon, $h$ is Planck's constant ($h=6.626\times 10^{- 34}\text{ J}\cdot\text{s}$), and $
u$ is the frequency of the photon.

Step2: Substitute the given values

We are given that $
u = 4.5\times10^{8}\text{ Hz}$. Substituting $h = 6.626\times 10^{-34}\text{ J}\cdot\text{s}$ and $
u=4.5\times 10^{8}\text{ Hz}$ into the formula $E = h
u$, we get $E=(6.626\times 10^{-34}\text{ J}\cdot\text{s})\times(4.5\times 10^{8}\text{ Hz})$.

Step3: Calculate the result

Using the rule of exponents for multiplication $a^{m}\times a^{n}=a^{m + n}$, we have $E=(6.626\times4.5)\times10^{-34 + 8}\text{ J}$.
$6.626\times4.5 = 29.817$, and $-34 + 8=-26$. So $E = 2.9817\times 10^{-25}\text{ J}$.

Answer:

$2.98\times 10^{-25}$