Question

for the piecewise linear function, find (a) f(-4), (b) f(-1), (c) f(0), (d) f(2), and (e) f(4).
$f(x)=\

$$\begin{cases}2x & \\text{if } x\\leq -1 \\\\ x - 1 & \\text{if } x > -1\\end{cases}$$

$
(a) $f(-4)= -8$
(b) $f(-1)=\square$

Explanation:

Step1: Determine the applicable function

Since \( -1 \leq -1 \), we use the first part of the piecewise function \( f(x) = 2x \).

Step2: Substitute \( x = -1 \) into the function

Substitute \( x = -1 \) into \( f(x) = 2x \), we get \( f(-1) = 2\times(-1) \).

Step3: Calculate the result

\( 2\times(-1) = -2 \).

Answer:

\( -2 \)