Question

place △abc so that its vertices are at a (-2,3), b (-9,4), and c (-6,-1). then place △abc so it is a ccw 90° rotation of △abc about the origin.

Explanation:

Step1: Recall rotation rule

The rule for a counter - clockwise 90° rotation about the origin is $(x,y)\to(-y,x)$.

Step2: Rotate point A

For point $A(-2,3)$, using the rule $(-y,x)$, we get $A'(-3, - 2)$.

Step3: Rotate point B

For point $B(-9,4)$, using the rule $(-y,x)$, we get $B'(-4,-9)$.

Step4: Rotate point C

For point $C(-6,-1)$, using the rule $(-y,x)$, we get $C'(1,-6)$.

Answer:

The vertices of $\triangle A'B'C'$ are $A'(-3,-2)$, $B'(-4,-9)$ and $C'(1,-6)$