Question

a positive charge of $6.0 \times 10^{-4}$ c is in an electric field that exerts a force of $4.5 \times 10^{-4}$ n on it. what is the strength of the electric field? $\frac{n}{c}$

Explanation:

Step1: Recall electric field formula

The electric field strength $E$ is defined as the force $F$ per unit charge $q$, so $E = \frac{F}{q}$.

Step2: Substitute given values

Substitute $F = 4.5 \times 10^{-4}\ \text{N}$ and $q = 6.0 \times 10^{-4}\ \text{C}$ into the formula:
$E = \frac{4.5 \times 10^{-4}}{6.0 \times 10^{-4}}$

Step3: Calculate the result

Simplify the expression: $E = 0.75$

Answer:

$0.75$ $\frac{\text{N}}{\text{C}}$