Question

is it possible to get a negative value under the radical when using the distance formula?
no
yes

Explanation:

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Since any real - number squared is non - negative, $(x_2 - x_1)^2\geq0$ and $(y_2 - y_1)^2\geq0$. So, the sum $(x_2 - x_1)^2+(y_2 - y_1)^2\geq0$.

Answer:

no