QUESTION IMAGE
Question
practice
see example 1
write each radical using rational exponents.
- $sqrt{3}$
- $sqrt3{7}$
- $sqrt3{3^2}$
- $sqrt4{3^5}$
ponents to determine
Step1: Convert root to rational exponent
For $\sqrt{5}$, recall $\sqrt[n]{a}=a^{\frac{1}{n}}$. Here $n=2$, so:
$\sqrt{5}=5^{\frac{1}{2}}$
Step2: Convert root to rational exponent
For $\frac{1}{\sqrt{7}}$, rewrite as $\sqrt{7}^{-1}$, then apply $\sqrt[n]{a}=a^{\frac{1}{n}}$:
$\frac{1}{\sqrt{7}}=7^{-\frac{1}{2}}$
Step3: Convert root to rational exponent
For $\sqrt[4]{3^2}$, use $\sqrt[n]{a^m}=a^{\frac{m}{n}}$. Here $n=4, m=2$:
$\sqrt[4]{3^2}=3^{\frac{2}{4}}=3^{\frac{1}{2}}$
Step4: Convert root to rational exponent
For $\sqrt[3]{x^5}$, use $\sqrt[n]{a^m}=a^{\frac{m}{n}}$. Here $n=3, m=5$:
$\sqrt[3]{x^5}=x^{\frac{5}{3}}$
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- $5^{\frac{1}{2}}$
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