Question

c) the pressure exerted by a liquid at a depth of 2.5m is 36750 pa. what is the density of the liquid to the nearest kg/m³? (take g = 10n/kg )

Explanation:

Step1: Recall pressure - density - depth formula

The formula for pressure exerted by a liquid is $P=
ho gh$, where $P$ is pressure, $
ho$ is density, $g$ is acceleration due to gravity, and $h$ is depth. We need to solve for $
ho$.

Step2: Rearrange the formula for density

From $P =
ho gh$, we can get $
ho=\frac{P}{gh}$.

Step3: Substitute the given values

We are given that $P = 36750\ Pa$, $g=10\ N/kg$, and $h = 2.5\ m$. Substituting these values into the formula $
ho=\frac{P}{gh}$, we have $
ho=\frac{36750}{10\times2.5}$.

Step4: Calculate the density

$
ho=\frac{36750}{25}=1470\ kg/m^{3}$.

Answer:

$1470\ kg/m^{3}$