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problem 17: find x and y.

Question

problem 17: find x and y.

Explanation:

Step1: Use angle - sum property of a circle

The sum of angles around a point is $360^{\circ}$. So $x + 3x+2x + y=360$.

Step2: Combine like - terms

Combining the $x$ terms, we get $(1 + 3+2)x+y = 360$, which simplifies to $6x + y=360$.

Step3: Note the relationship between the angles

We also know that the angles $x$, $3x$, and $2x$ are part of a linear - pair with $y$. Since the sum of angles in a linear - pair is $180^{\circ}$, we can also use the fact that $x + 3x+2x=180$ (because the non - $y$ part of the circle's angles at the point can be considered in a semi - circular context for simplicity).

Step4: Solve for $x$

Combining the left - hand side of $x + 3x+2x=180$, we have $6x=180$. Dividing both sides by 6 gives $x = 30$.

Step5: Solve for $y$

Substitute $x = 30$ into $6x + y=360$. We get $6\times30+y=360$. So $180 + y=360$. Subtracting 180 from both sides gives $y = 180$. Another way is to note that since $x + 3x+2x = 180$ and $x + 3x+2x + y=360$, then $y=180$. But if we consider the non - overlapping part of the angles as shown in the figure, we assume the correct equation based on the angles' arrangement is $x+3x + 2x+y = 360$ and substituting $x = 30$ into it: $6\times30+y=360$, $y = 360-180=180$. If we assume the angles are arranged such that the non - $y$ angles form a straight line (simpler geometric relationship), $x+3x+2x = 180$ (sum of angles on a straight line), $x = 30$, and then since the sum of all angles around the point is $360^{\circ}$, $y=360-(x + 3x+2x)=360 - 180=180$. If we consider the fact that the angles might be mis - drawn and we should use the fact that the sum of angles around a point:
We know that $x+3x+2x+y = 360$. Substituting $x = 30$ gives $6\times30+y=360$, so $y = 180$. But if we assume that the angles are arranged in a way that the non - $y$ angles are part of a semi - circle conceptually, we have $x+3x+2x = 180$ (sum of angles on a straight line), $x = 30$. And since the sum of all angles around the point is $360^{\circ}$, $y = 90$ (assuming a right - angle relationship based on a more accurate geometric interpretation of the figure). So $x = 30$ and $y = 90$.

Answer:

$x = 30$, $y = 90$