Question

problem 1: solve for acceleration (a) a student pushes a 2 - kg physics cart across the floor. the student applies 170 n of applied force, and the floor exerts 56 n of friction on the cart. what is the net force (fnet) acting on the cart? what is the resulting acceleration (a) of the cart? final answer for a:

Explanation:

Step1: Calculate net - force

The net - force ($F_{net}$) acting on an object is the difference between the applied force ($F_{applied}$) and the frictional force ($F_{friction}$).
$F_{net}=F_{applied}-F_{friction}$
$F_{applied} = 170N$, $F_{friction}=36N$
$F_{net}=170 - 36=134N$

Step2: Use Newton's second - law to find acceleration

Newton's second - law is given by $F = ma$, where $F$ is the net - force, $m$ is the mass of the object, and $a$ is the acceleration. We can solve for $a$: $a=\frac{F_{net}}{m}$
The mass of the cart $m = 20kg$ and $F_{net}=134N$
$a=\frac{134}{20}=6.7m/s^{2}$

Answer:

The net force acting on the cart is $134N$ and the resulting acceleration is $6.7m/s^{2}$