Question

1. problem solving you, your friend, and your cousin have a basketball competition where each person attempts the same number of shots. you make 70% of your shots, your friend makes \\(\frac{7}{9}\\) of her shots, and your cousin makes 0.72 of his shots. how many times more shots are made by the first - place finisher than the third - place finisher?\\(\bigcirc\\) 0.1 times more shots\\(\bigcirc\\) 0.3 times more shots\\(\bigcirc\\) 1.1 times more shots\\(\bigcirc\\) 2.3 times more shots

Explanation:

Step1: Convert all values to decimals

You: $70\% = 0.7$
Friend: $\frac{7}{9} = 0.\overline{7}$
Cousin: $0.\overline{72}$

Step2: Rank the values from highest to lowest

First place: Friend ($0.\overline{7}$), Third place: You ($0.7$)

Step3: Calculate the ratio of first to third

$\frac{0.\overline{7}}{0.7} = \frac{\frac{7}{9}}{\frac{7}{10}} = \frac{7}{9} \times \frac{10}{7} = \frac{10}{9} = 1.\overline{1}$

Answer:

$\boldsymbol{1.\overline{1}}$ times more shots (the second option)