Question

problems 5–6: solve each equatio

1. \\(\frac{1}{9}(2m - 16) = \frac{1}{3}(2m + 4)\\)

Explanation:

Step1: Eliminate denominators

Multiply both sides by 9:
$$9 \times \frac{1}{9}(2m - 16) = 9 \times \frac{1}{3}(2m + 4)$$
Simplify to get:
$$2m - 16 = 3(2m + 4)$$

Step2: Expand right-hand side

Distribute the 3:
$$2m - 16 = 6m + 12$$

Step3: Isolate m terms

Subtract $2m$ from both sides:
$$-16 = 4m + 12$$

Step4: Isolate constant terms

Subtract 12 from both sides:
$$-28 = 4m$$

Step5: Solve for m

Divide both sides by 4:
$$m = \frac{-28}{4}$$

Answer:

$m = -7$