Question

product of (2x - 10) and (x + 8).

Explanation:

Step1: Apply distributive property (FOIL)

To find the product of \((2x - 10)\) and \((x + 8)\), we use the distributive property (also known as the FOIL method for binomials). The formula for \((a + b)(c + d)=ac+ad+bc+bd\). Here, \(a = 2x\), \(b=- 10\), \(c = x\), \(d = 8\).

So, \((2x-10)(x + 8)=2x\times x+2x\times8+(- 10)\times x+(-10)\times8\)

Step2: Simplify each term

Simplify each product:

• \(2x\times x = 2x^{2}\)
• \(2x\times8=16x\)
• \(-10\times x=-10x\)
• \(-10\times8 = - 80\)

Step3: Combine like terms

Now, combine the like terms (\(16x\) and \(-10x\)):

\(2x^{2}+16x-10x - 80=2x^{2}+(16x - 10x)-80=2x^{2}+6x - 80\)

Answer:

\(2x^{2}+6x - 80\)