Question

prove: the difference of two even integers is even. 2n - 2m = ?(n - m) = even

Explanation:

Step1: Factor out the common term

We have the expression \(2n - 2m\). Notice that both terms have a common factor of \(2\). Using the distributive property of multiplication over subtraction (i.e., \(ab - ac=a(b - c)\)), we can factor out \(2\) from both terms.
So, \(2n-2m = 2(n - m)\).

Answer:

\(2\)