Question

proving the law of sines. two right triangles, △abd and △acd, were created from △abc by constructing ad ⊥ cb. follow these steps to prove that $\frac{sin(b)}{b}=\frac{sin(c)}{c}$. 1. for △abd, sin(b) = $\frac{h}{c}$. 2. multiply both sides of the equation by c and simplify. the equation sin(b) = $\frac{h}{c}$ becomes c sin(b)=h. 3. for △acd, sin(c) = $\frac{h}{b}$. 4. multiply both sides of the equation by b and simplify. the equation sin(c) = $\frac{h}{b}$ becomes

Explanation:

Step1: Given $\sin(C)=\frac{h}{b}$

We need to multiply both sides by $b$.

Step2: Multiply by $b$

$b\times\sin(C)=b\times\frac{h}{b}$

Step3: Simplify

$b\sin(C)=h$

Answer:

$b\sin(C)=h$