QUESTION IMAGE
Question
put the following equation of a line into slope - intercept form, simplifying all fractions. 3x + 6y = 36
Step1: Isolate the y - term
Subtract \(3x\) from both sides of the equation \(3x + 6y=36\) to get \(6y=- 3x + 36\).
Step2: Solve for y
Divide each term in the equation \(6y=-3x + 36\) by 6. So we have \(y=\frac{-3x}{6}+\frac{36}{6}\).
Step3: Simplify the fractions
Simplify \(\frac{-3x}{6}\) to \(-\frac{1}{2}x\) and \(\frac{36}{6}\) to 6. So the equation becomes \(y =-\frac{1}{2}x + 6\).
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\(y=-\frac{1}{2}x + 6\)