Question

pythagorean theorem and simplifying radicals practice
18 of 32
simplify.

1. $3\sqrt{140}$

Explanation:

Step1: Factor radicand into perfect square

$140 = 4 \times 35$

Step2: Separate perfect square radical

$3\sqrt{140} = 3\sqrt{4 \times 35} = 3 \times \sqrt{4} \times \sqrt{35}$

Step3: Simplify perfect square root

$\sqrt{4}=2$, so $3 \times 2 \times \sqrt{35} = 6\sqrt{35}$

Answer:

$6\sqrt{35}$ (Fill 6 in the first box and 35 in the second box)