Question

q28.) a spinner has ten equal sections numbered one through ten. what is the probability that the pointer will land on an odd number when the arrow is spun? answer

Explanation:

Step1: Identify total outcomes

The spinner has 10 equal - sections numbered 1 through 10, so the total number of possible outcomes is $n = 10$.

Step2: Identify favorable outcomes

The odd - numbered sections are 1, 3, 5, 7, 9. So the number of favorable outcomes is $m=5$.

Step3: Calculate probability

The probability $P$ of an event is given by the formula $P=\frac{m}{n}$. Substituting $m = 5$ and $n = 10$ into the formula, we get $P=\frac{5}{10}=\frac{1}{2}$.

Answer:

$\frac{1}{2}$