Question

if a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true? the figure must be an isosceles trapezoid because it has 2 congruent base angles. the figure must be a rectangle because all rectangles have exactly 2 lines of symmetry. the figure could be a rhombus because the 2 lines of symmetry bisect the angles. the figure could be a square because the diagonals of a square bisect the right angles.

Explanation:

Step1: Analyze isosceles trapezoid

An isosceles trapezoid has 1 line of symmetry, not 2 angle - bisecting lines of symmetry.

Step2: Analyze rectangle

A rectangle has 2 lines of symmetry, but they are not angle - bisectors (except for a square which is a special rectangle).

Step3: Analyze rhombus

A rhombus has 2 lines of symmetry which are its diagonals, and the diagonals of a rhombus are angle - bisectors.

Step4: Analyze square

A square has 4 lines of symmetry, not exactly 2.

Answer:

The figure could be a rhombus because the 2 lines of symmetry bisect the angles.