Question

quel graphique de fonction de transition correspond au réseau à quatre bornes dont le circuit est représenté sur la figure ?

Explanation:

Step1: Analyze RL - circuit transfer function

The given circuit is an RL - series circuit. The transfer function \(H(s)=\frac{U_{out}(s)}{U_{in}(s)}=\frac{sL}{sL + R}\). Taking the inverse - Laplace transform for a step input \(U_{in}(s)=\frac{1}{s}\), we get \(u_{out}(t)=1 - e^{-\frac{R}{L}t}\).

Step2: Match with graphs

The function \(u_{out}(t)=1 - e^{-\frac{R}{L}t}\) is a rising exponential function that starts from \(0\) and approaches \(1\) as \(t
ightarrow\infty\). Graph 'c' shows a function that starts from \(0\) and rises asymptotically to a non - zero value, which is consistent with the behavior of the output of the RL circuit for a step input.

Answer:

C. c