Question

question 1-5
factor completely: 7y + 2xy - 10x - 35
○ (y - 5)(2x + 7)
○ y(7 + 2x) + 5(-2x - 7)
○ y(7 - 3x) - 5(3x - 5)
○ not factorable

Explanation:

Step1: Group terms

Group the first two terms and the last two terms: \((7y + 2xy)+(-10x - 35)\)

Step2: Factor out GCF from each group

Factor out \(y\) from the first group and \(-5\) from the second group: \(y(7 + 2x)-5(2x + 7)\)

Step3: Factor out common binomial

Notice that \((7 + 2x)\) and \((2x + 7)\) are the same, so factor out \((2x + 7)\) (or \((7 + 2x)\)): \((y - 5)(2x + 7)\) (since \(y(7 + 2x)-5(2x + 7)=(y - 5)(2x + 7)\))

Answer:

\((y - 5)(2x + 7)\) (the first option: \((y - 5)(2x + 7)\))