Question

question 9 of 10
a 12 - foot ladder is leaning against a building. the ladder makes a 45 - degree angle with the building. how far up the building does the ladder reach?
a. 6 feet
b. 6\sqrt{2} feet
c. 12\sqrt{2} feet
d. 24\sqrt{2} feet

Explanation:

Step1: Use sine function

Let the height up the building be $h$. $\sin45^{\circ}=\frac{h}{12}$.

Step2: Solve for $h$

Since $\sin45^{\circ}=\frac{\sqrt{2}}{2}$, we have $h = 12\times\frac{\sqrt{2}}{2}=6\sqrt{2}$.

Answer:

B. $6\sqrt{2}$ feet