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Question
question 2 of 10 how many solutions are there to the equation below? 6x + 30 + 4x = 10(x + 3) a. 0 b. 1 c. infinitely many
Step1: Combine like terms on the left
$6x + 4x + 30 = 10x + 30$
Step2: Expand the right side
$10(x + 3) = 10x + 30$
Step3: Compare both sides
Left: $10x + 30$, Right: $10x + 30$. They are identical, so any $x$ satisfies the equation.
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C. Infinitely many