Question

question 7 of 10
a stuntman jumps from the roof of a building to the safety net below. how far has the stuntman fallen after 2.3 seconds?
a. 21.2 m
b. 9.8 m
c. 11.3 m
d. 25.9 m

Explanation:

Step1: Identify the formula

The formula for the distance fallen in free - fall is $d = v_0t+\frac{1}{2}gt^2$. Since the stuntman starts from rest, $v_0 = 0$. So the formula simplifies to $d=\frac{1}{2}gt^2$, where $g = 9.8\ m/s^2$ and $t = 2.3\ s$.

Step2: Substitute values

Substitute $g = 9.8\ m/s^2$ and $t = 2.3\ s$ into the formula $d=\frac{1}{2}gt^2$. We get $d=\frac{1}{2}\times9.8\times(2.3)^2$.
First, calculate $(2.3)^2=5.29$. Then $\frac{1}{2}\times9.8\times5.29 = 4.9\times5.29$.
$4.9\times5.29 = 25.921\approx25.9\ m$.

Answer:

D. 25.9 m