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Question
question 3 of 10 what is the length of $overline{cd}$? in this diagram, $\triangle abcsim\triangle edc$.
Step1: Use similarity of triangles
Since $\triangle ABC\sim\triangle EDC$, we have $\frac{AC}{EC}=\frac{BC}{DC}$. So $\frac{21}{7}=\frac{20 - x}{x}$.
Step2: Cross - multiply
$21x = 7(20 - x)$.
Step3: Expand and solve
$21x=140 - 7x$, $28x = 140$, $x = 5$.
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B. 5