Question

question: if $f(x)=(4x + 2)^2$, then $f(1)=$? a 6 b 12 c 20 d 36

Explanation:

Step1: Substitute x = 1 into the function.

Substitute \(x = 1\) into \(f(x)=(4x + 2)^2\), we get \(f(1)=(4\times1+ 2)^2\).

Step2: Calculate the value inside the parentheses first.

\(4\times1+2=4 + 2=6\).

Step3: Calculate the square.

\(f(1)=6^2=36\).

Answer:

D. 36