Question

question 2
0/12 pts 2 details
part 1 of 4
for the following problem, you will need the formulas below.
the mean/expected value of a discrete probability distribution is: $mu=sum xcdot p(x)$.
the standard deviation of a discrete probability distribution is: $sigma = sqrt{sum x^{2}cdot p(x)-mu^{2}}$.
assume that 54.9% of the world is female. suppose we pick 5 people at random, and let x represent the number of females in this group. the probability distribution for x is given below, with one value missing.
enter the missing probability in the table below, rounded to 3 significant figures.

x	p(x)
0	0.02
1	0.11
2	0.28

|3|

4	0.20
5	0.05

Explanation:

Step1: Recall probability - sum property

The sum of all probabilities in a probability distribution is 1.

Step2: Set up the equation

Let the missing probability be $p$. Then $0.02 + 0.11+0.28 + p+0.20 + 0.05=1$.

Step3: Solve for $p$

First, add the known probabilities: $0.02+0.11 + 0.28+0.20 + 0.05=0.66$. Then $p = 1 - 0.66=0.340$.

Answer:

$0.340$