Question

question 14 (4 points) solve the quadratic using your preferred method. upload your handwritten work displaying how you solved to receive credit. $x^2 + 6x = -18$

Explanation:

Step1: Rewrite in standard form

$x^2 + 6x + 18 = 0$

Step2: Identify coefficients

For $ax^2+bx+c=0$, $a=1$, $b=6$, $c=18$

Step3: Use quadratic formula

$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Step4: Substitute values

$x = \frac{-6 \pm \sqrt{6^2-4(1)(18)}}{2(1)}$

Step5: Simplify discriminant

$\sqrt{36-72} = \sqrt{-36} = 6i$

Step6: Compute final values

$x = \frac{-6 \pm 6i}{2} = -3 \pm 3i$

Answer:

$x = -3 + 3i$ and $x = -3 - 3i$